-0.25x^2+2x+1.5=0

Solution for -0.25x^2+2x+1.5=0 equation:

-0.25x^2+2x+1.5=0

a = -0.25; b = 2; c = +1.5;
Δ = b2-4ac
Δ = 22-4·(-0.25)·1.5
Δ = 5.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{5.5}}{2*-0.25}=\frac{-2-\sqrt{5.5}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{5.5}}{2*-0.25}=\frac{-2+\sqrt{5.5}}{-0.5}
$